Question: If the electric potential at a point is 100 V and the electric field is 50 N/C, what is the distance from the charge?
Options:
2 m
1 m
0.5 m
4 m
Correct Answer: 2 m
Solution:
Distance d = V / E = 100 V / 50 N/C = 2 m.
If the electric potential at a point is 100 V and the electric field is 50 N/C,
Practice Questions
Q1
If the electric potential at a point is 100 V and the electric field is 50 N/C, what is the distance from the charge?
2 m
1 m
0.5 m
4 m
Questions & Step-by-Step Solutions
If the electric potential at a point is 100 V and the electric field is 50 N/C, what is the distance from the charge?
Step 1: Identify the given values. We have the electric potential (V) which is 100 volts and the electric field (E) which is 50 newtons per coulomb.
Step 2: Understand the formula to find the distance (d) from the charge. The formula is d = V / E.
Step 3: Substitute the values into the formula. Replace V with 100 V and E with 50 N/C: d = 100 V / 50 N/C.
Step 4: Perform the division. Calculate 100 divided by 50, which equals 2.
Step 5: State the result. The distance from the charge is 2 meters.
Electric Potential and Electric Field Relationship – The relationship between electric potential (V), electric field (E), and distance (d) is given by the formula d = V / E.
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