What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1

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Question: What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))

Options:

Correct Answer: 1.23 atm

Solution:

Osmotic pressure (π) = nRT/V = (0.5 moles * 0.0821 * 298) / 1 = 12.3 atm.

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))

What is the osmotic pressure of a solution containing 0.5 moles of glucose in 1 L of water at 25 °C? (R = 0.0821 L·atm/(K·mol))

Step 1: Identify the formula for osmotic pressure, which is π = nRT/V.
Step 2: Determine the values needed for the formula: n (number of moles) = 0.5 moles, R (ideal gas constant) = 0.0821 L·atm/(K·mol), T (temperature in Kelvin) = 25 °C + 273 = 298 K, and V (volume in liters) = 1 L.
Step 3: Plug the values into the formula: π = (0.5 moles * 0.0821 L·atm/(K·mol) * 298 K) / 1 L.
Step 4: Calculate the numerator: 0.5 * 0.0821 * 298 = 12.3.
Step 5: Since the volume is 1 L, the osmotic pressure is simply 12.3 atm.

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