In a circuit, two capacitors of capacitance 3μF and 6μF are connected in paralle

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Question: In a circuit, two capacitors of capacitance 3μF and 6μF are connected in parallel. What is the total capacitance?

Options:

Correct Answer: 9μF

Solution:

In parallel, the total capacitance is the sum: C_total = C1 + C2 = 3μF + 6μF = 9μF.

In a circuit, two capacitors of capacitance 3μF and 6μF are connected in parallel. What is the total capacitance?

In a circuit, two capacitors of capacitance 3μF and 6μF are connected in parallel. What is the total capacitance?

Step 1: Identify the capacitance values of the two capacitors. The first capacitor (C1) has a capacitance of 3μF, and the second capacitor (C2) has a capacitance of 6μF.
Step 2: Understand that when capacitors are connected in parallel, the total capacitance (C_total) is found by adding the capacitance values together.
Step 3: Write the formula for total capacitance in parallel: C_total = C1 + C2.
Step 4: Substitute the values into the formula: C_total = 3μF + 6μF.
Step 5: Perform the addition: 3μF + 6μF = 9μF.
Step 6: Conclude that the total capacitance of the circuit is 9μF.

Capacitance in Parallel Circuits – In parallel circuits, the total capacitance is the sum of the individual capacitances.