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If the balancing length of a potentiometer is found to be 40 cm for a cell of em

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Question: If the balancing length of a potentiometer is found to be 40 cm for a cell of emf 2V, what is the potential gradient if the total length of the wire is 100 cm?

Options:

  1. 5 V/m
  2. 2 V/m
  3. 4 V/m
  4. 3 V/m

Correct Answer: 5 V/m

Solution: 

The potential gradient is V/L = 2V/0.4m = 5 V/m.

If the balancing length of a potentiometer is found to be 40 cm for a cell of em

Practice Questions

Q1
If the balancing length of a potentiometer is found to be 40 cm for a cell of emf 2V, what is the potential gradient if the total length of the wire is 100 cm?
  1. 5 V/m
  2. 2 V/m
  3. 4 V/m
  4. 3 V/m

Questions & Step-by-Step Solutions

If the balancing length of a potentiometer is found to be 40 cm for a cell of emf 2V, what is the potential gradient if the total length of the wire is 100 cm?
  • Step 1: Understand that the balancing length of the potentiometer is the length of wire where the voltage is balanced by the cell's emf.
  • Step 2: Note that the balancing length given is 40 cm. Convert this to meters: 40 cm = 0.4 m.
  • Step 3: Identify the emf of the cell, which is given as 2V.
  • Step 4: The potential gradient is calculated using the formula: Potential Gradient = Voltage / Length of wire.
  • Step 5: Substitute the values into the formula: Potential Gradient = 2V / 0.4m.
  • Step 6: Perform the division: 2V / 0.4m = 5 V/m.
  • Step 7: Conclude that the potential gradient is 5 V/m.
  • Potentiometer Basics – Understanding how a potentiometer measures emf and the relationship between balancing length, emf, and potential gradient.
  • Potential Gradient Calculation – Calculating the potential gradient using the formula V/L, where V is the emf and L is the balancing length.
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