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In a potentiometer setup, if the known voltage is 6V and the unknown voltage is

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Question: In a potentiometer setup, if the known voltage is 6V and the unknown voltage is balanced at 30 cm, what is the potential gradient if the total length of the wire is 120 cm?

Options:

  1. 2 V/m
  2. 1.5 V/m
  3. 3 V/m
  4. 4 V/m

Correct Answer: 1.5 V/m

Solution:

The potential gradient is V/L = 6V/0.3m = 20 V/m, but since the total length is 1.2m, the gradient is 5 V/m.

In a potentiometer setup, if the known voltage is 6V and the unknown voltage is

Practice Questions

Q1
In a potentiometer setup, if the known voltage is 6V and the unknown voltage is balanced at 30 cm, what is the potential gradient if the total length of the wire is 120 cm?
  1. 2 V/m
  2. 1.5 V/m
  3. 3 V/m
  4. 4 V/m

Questions & Step-by-Step Solutions

In a potentiometer setup, if the known voltage is 6V and the unknown voltage is balanced at 30 cm, what is the potential gradient if the total length of the wire is 120 cm?
  • Step 1: Identify the known voltage, which is 6V.
  • Step 2: Identify the length at which the unknown voltage is balanced, which is 30 cm.
  • Step 3: Convert the balanced length from cm to meters: 30 cm = 0.3 m.
  • Step 4: Calculate the potential gradient using the formula: Potential Gradient = Voltage / Length.
  • Step 5: Substitute the known values into the formula: Potential Gradient = 6V / 0.3m.
  • Step 6: Perform the calculation: 6V / 0.3m = 20 V/m.
  • Step 7: Identify the total length of the wire, which is 120 cm.
  • Step 8: Convert the total length from cm to meters: 120 cm = 1.2 m.
  • Step 9: Calculate the final potential gradient using the total length: Potential Gradient = 6V / 1.2m.
  • Step 10: Perform the calculation: 6V / 1.2m = 5 V/m.
  • Potential Gradient – The potential gradient is the change in voltage per unit length of the wire, calculated as the known voltage divided by the length at which the unknown voltage is balanced.
  • Potentiometer Principle – A potentiometer measures unknown voltages by balancing them against a known voltage, allowing for precise voltage measurements.
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