In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω),

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Question: In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?

Options:

Correct Answer: 16V

Solution:

Using voltage division, V_R2 = V_total * (R2 / (R1 + R2)) = 24V * (16Ω / (8Ω + 16Ω)) = 16V.

In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?

In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the voltage across R2?

Step 1: Identify the total voltage in the circuit, which is given as 24V from the battery.
Step 2: Identify the values of the resistors: R1 = 8Ω and R2 = 16Ω.
Step 3: Calculate the total resistance in the circuit by adding R1 and R2: Total Resistance = R1 + R2 = 8Ω + 16Ω = 24Ω.
Step 4: Use the voltage division formula to find the voltage across R2: V_R2 = V_total * (R2 / Total Resistance).
Step 5: Substitute the values into the formula: V_R2 = 24V * (16Ω / 24Ω).
Step 6: Simplify the fraction: 16Ω / 24Ω = 2/3.
Step 7: Multiply 24V by 2/3 to find V_R2: V_R2 = 24V * (2/3) = 16V.

Voltage Division – The principle that the voltage across a resistor in a series circuit is a fraction of the total voltage, proportional to the resistance of that resistor.