What is the total resistance of two 8Ω resistors connected in series?

₹0.0

Question: What is the total resistance of two 8Ω resistors connected in series?

Options:

Correct Answer: 16Ω

Solution:

In series, R_eq = R1 + R2 = 8 + 8 = 16Ω.

What is the total resistance of two 8Ω resistors connected in series?

What is the total resistance of two 8Ω resistors connected in series?

Step 1: Identify the resistors. We have two resistors, each with a resistance of 8Ω.
Step 2: Understand that when resistors are connected in series, their total resistance is the sum of their individual resistances.
Step 3: Write down the formula for total resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 8Ω + 8Ω.
Step 5: Calculate the total resistance: 8 + 8 = 16Ω.
Step 6: Conclude that the total resistance of the two 8Ω resistors in series is 16Ω.

No concepts available.