In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles

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Question: In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles of H2 are required?

Options:

Correct Answer: 6 moles

Solution:

According to the stoichiometry, 1 mole of O2 requires 2 moles of H2. Therefore, 3 moles of O2 will require 3 x 2 = 6 moles of H2.

In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles of H2 are required?

In the reaction 2H2 + O2 → 2H2O, if 3 moles of O2 are available, how many moles of H2 are required?

Step 1: Look at the chemical equation: 2H2 + O2 → 2H2O.
Step 2: Identify the ratio of O2 to H2 in the equation. For every 1 mole of O2, 2 moles of H2 are needed.
Step 3: Determine how many moles of O2 you have. In this case, you have 3 moles of O2.
Step 4: Use the ratio from Step 2. Since 1 mole of O2 needs 2 moles of H2, multiply the number of moles of O2 (3) by 2.
Step 5: Calculate: 3 moles of O2 x 2 moles of H2 = 6 moles of H2.
Step 6: Conclude that you need 6 moles of H2 for 3 moles of O2.

Stoichiometry – The calculation of reactants and products in chemical reactions based on balanced equations.