What is the mass of 0.75 moles of sulfuric acid (H2SO4)?

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Question: What is the mass of 0.75 moles of sulfuric acid (H2SO4)?

Options:

Correct Answer: 98 g

Solution:

Molar mass of H2SO4 = 2*1 + 32 + 4*16 = 98 g/mol. Mass = moles x molar mass = 0.75 moles x 98 g/mol = 73.5 g.

What is the mass of 0.75 moles of sulfuric acid (H2SO4)?

What is the mass of 0.75 moles of sulfuric acid (H2SO4)?

Step 1: Identify the chemical formula of sulfuric acid, which is H2SO4.
Step 2: Calculate the molar mass of H2SO4 by adding the atomic masses of its elements: 2 hydrogen (H), 1 sulfur (S), and 4 oxygen (O).
Step 3: The atomic mass of hydrogen (H) is approximately 1 g/mol, sulfur (S) is approximately 32 g/mol, and oxygen (O) is approximately 16 g/mol.
Step 4: Calculate the total mass: 2*1 (for H) + 32 (for S) + 4*16 (for O) = 2 + 32 + 64 = 98 g/mol.
Step 5: Use the formula for mass: Mass = moles x molar mass.
Step 6: Substitute the values: Mass = 0.75 moles x 98 g/mol.
Step 7: Calculate the mass: 0.75 x 98 = 73.5 g.

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