What is the principal quantum number (n) for the outermost electron in rubidium

₹0.0

Question: What is the principal quantum number (n) for the outermost electron in rubidium (Rb)?

Options:

Correct Answer: 4

Solution:

Rubidium (Rb) has an atomic number of 37, and its outermost electron is in the 5th shell (n=5).

What is the principal quantum number (n) for the outermost electron in rubidium (Rb)?

What is the principal quantum number (n) for the outermost electron in rubidium (Rb)?

Step 1: Find the atomic number of rubidium (Rb). The atomic number is 37.
Step 2: Determine the electron configuration of rubidium. The configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s¹.
Step 3: Identify the outermost electron in the electron configuration. The outermost electron is in the 5s orbital.
Step 4: Determine the principal quantum number (n) for the outermost electron. The outermost electron is in the 5th shell, so n = 5.

No concepts available.