What is the equation of the line parallel to y = 2x + 3 that passes through the

₹0.0

Question: What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?

Options:

Correct Answer: y = 2x - 1

Solution:

Parallel lines have the same slope: y - 1 = 2(x - 1) => y = 2x - 1.

What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?

What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?

Step 1: Identify the slope of the given line. The equation is y = 2x + 3, so the slope (m) is 2.
Step 2: Since parallel lines have the same slope, the slope of the new line will also be 2.
Step 3: Use the point-slope form of the equation of a line, which is y - y1 = m(x - x1). Here, (x1, y1) is the point (1, 1) and m is 2.
Step 4: Substitute the values into the point-slope form: y - 1 = 2(x - 1).
Step 5: Simplify the equation. Distribute the 2: y - 1 = 2x - 2.
Step 6: Add 1 to both sides to solve for y: y = 2x - 1.

No concepts available.