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What is the reducing agent in the reaction Zn + CuSO4 β†’ ZnSO4 + Cu?

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Question: What is the reducing agent in the reaction Zn + CuSO4 β†’ ZnSO4 + Cu?

Options:

  1. Zn
  2. Cu
  3. CuSO4
  4. ZnSO4

Correct Answer: Zn

Solution:

Zinc (Zn) is the reducing agent as it donates electrons to copper.

What is the reducing agent in the reaction Zn + CuSO4 β†’ ZnSO4 + Cu?

Practice Questions

Q1
What is the reducing agent in the reaction Zn + CuSO4 β†’ ZnSO4 + Cu?
  1. Zn
  2. Cu
  3. CuSO4
  4. ZnSO4

Questions & Step-by-Step Solutions

What is the reducing agent in the reaction Zn + CuSO4 β†’ ZnSO4 + Cu?
  • Step 1: Identify the reactants in the reaction: Zn (zinc) and CuSO4 (copper sulfate).
  • Step 2: Understand what a reducing agent does: It donates electrons to another substance.
  • Step 3: Look at the products of the reaction: ZnSO4 (zinc sulfate) and Cu (copper).
  • Step 4: Determine which element is being reduced: Copper (Cu) is being reduced because it goes from Cu^2+ in CuSO4 to Cu (0) in the products.
  • Step 5: Identify which element is oxidized: Zinc (Zn) is oxidized because it goes from Zn (0) to Zn^2+ in ZnSO4.
  • Step 6: Conclude that since zinc donates electrons to copper, zinc is the reducing agent.
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