For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the

₹0.0

Question: For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the rate of disappearance of A?

Options:

Correct Answer: 1.0 mol/L/s

Solution:

The rate of disappearance of A is equal to the rate of formation of B, multiplied by the stoichiometric coefficients. Here, it is 1.0 mol/L/s.

For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the rate of disappearance of A?

For a reaction A → B, if the rate of formation of B is 0.5 mol/L/s, what is the rate of disappearance of A?

Step 1: Identify the reaction: A → B.
Step 2: Understand that the rate of formation of B is given as 0.5 mol/L/s.
Step 3: Recognize that for every 1 mole of A that disappears, 1 mole of B is formed (stoichiometric coefficients are both 1).
Step 4: Since the rate of formation of B is 0.5 mol/L/s, the rate of disappearance of A will be the same, but we need to multiply by the stoichiometric coefficient of A, which is 1.
Step 5: Calculate the rate of disappearance of A: 0.5 mol/L/s * 1 = 0.5 mol/L/s.
Step 6: Conclude that the rate of disappearance of A is 0.5 mol/L/s.

Rate of Reaction – The relationship between the rate of formation of products and the rate of disappearance of reactants in a chemical reaction.
Stoichiometry – The use of coefficients in a balanced chemical equation to relate the amounts of reactants and products.