If 1 mole of NaCl is dissolved in water, how many particles are present in solut

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Question: If 1 mole of NaCl is dissolved in water, how many particles are present in solution?

Options:

Correct Answer: 2

Solution:

1 mole of NaCl dissociates into 2 particles (1 Na⁺ and 1 Cl⁻), so there are 2 particles in solution.

If 1 mole of NaCl is dissolved in water, how many particles are present in solution?

If 1 mole of NaCl is dissolved in water, how many particles are present in solution?

Step 1: Understand that 1 mole of a substance contains a specific number of particles, known as Avogadro's number, which is approximately 6.022 x 10^23.
Step 2: Recognize that when NaCl (table salt) is dissolved in water, it breaks apart into its ions: sodium (Na⁺) and chloride (Cl⁻).
Step 3: Note that 1 mole of NaCl produces 1 mole of Na⁺ ions and 1 mole of Cl⁻ ions when it dissolves.
Step 4: Since each mole of NaCl produces 2 moles of particles (1 Na⁺ and 1 Cl⁻), we can calculate the total number of particles.
Step 5: Multiply the number of moles (1 mole) by the number of particles produced per mole (2), which gives us 2 moles of particles.
Step 6: Finally, multiply the total moles of particles (2) by Avogadro's number (6.022 x 10^23) to find the total number of particles in solution.

Mole Concept – Understanding that 1 mole of a substance contains Avogadro's number of particles (approximately 6.022 x 10²³).
Dissociation of Ionic Compounds – Recognizing that ionic compounds like NaCl dissociate into their constituent ions in solution.