What is the product of the E1 elimination of 2-bromo-2-methylpropane?

What is the product of the E1 elimination of 2-bromo-2-methylpropane?

Step 1: Start with the molecule 2-bromo-2-methylpropane, which has a bromine atom attached to a carbon that is also connected to three other carbon atoms.
Step 2: The first part of the E1 elimination is the loss of the bromine atom. This creates a carbocation (a positively charged carbon) because the bromine leaves.
Step 3: The carbocation is now unstable and can lose a hydrogen atom from a neighboring carbon. This step forms a double bond.
Step 4: The result of losing the hydrogen atom and forming a double bond is the product 2-methylpropene, which is the major product of the reaction.

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