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A is 4 years older than B. If the sum of their ages is 28 years, how old is A?
A is 4 years older than B. If the sum of their ages is 28 years, how old is A?
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Practice Questions
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Q1
A is 4 years older than B. If the sum of their ages is 28 years, how old is A?
12
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16
18
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Let B's age be x. Then A's age is x + 4. So, x + (x + 4) = 28. Solving gives x = 12, so A = 16.
Questions & Step-by-step Solutions
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Q
Q: A is 4 years older than B. If the sum of their ages is 28 years, how old is A?
Solution:
Let B's age be x. Then A's age is x + 4. So, x + (x + 4) = 28. Solving gives x = 12, so A = 16.
Steps: 7
Show Steps
Step 1: Let B's age be represented by the variable x.
Step 2: Since A is 4 years older than B, we can express A's age as x + 4.
Step 3: The problem states that the sum of A's age and B's age is 28 years. We can write this as: x + (x + 4) = 28.
Step 4: Simplify the equation: Combine like terms to get 2x + 4 = 28.
Step 5: Subtract 4 from both sides of the equation: 2x = 28 - 4, which simplifies to 2x = 24.
Step 6: Divide both sides by 2 to solve for x: x = 24 / 2, which gives x = 12.
Step 7: Now that we know B's age (x) is 12, we can find A's age: A = x + 4 = 12 + 4, which equals 16.
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