A 3 kg object is dropped from a height of 12 m. What is the potential energy at

A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?

A 3 kg object is dropped from a height of 12 m. What is the potential energy at the top?

Step 1: Identify the mass of the object. In this case, the mass (m) is 3 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 12 m.
Step 3: Identify the acceleration due to gravity. The value of g is approximately 9.8 m/s².
Step 4: Use the formula for potential energy, which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 3 kg × 9.8 m/s² × 12 m.
Step 6: Calculate the result: 3 × 9.8 × 12 = 352.8 J.
Step 7: Conclude that the potential energy at the top is 352.8 Joules.

Potential Energy – Potential energy is the energy possessed by an object due to its position in a gravitational field, calculated using the formula PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.