Ten years ago, the age of a man was 3 times the age of his son. If the son is no

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Question: Ten years ago, the age of a man was 3 times the age of his son. If the son is now 10 years old, how old is the man now?

Options:

Correct Answer: 40

Solution:

Ten years ago, the son was 10 - 10 = 0 years old. The man was 3 * 0 = 0 years old then, so now he is 10 + 30 = 40 years old.

Ten years ago, the age of a man was 3 times the age of his son. If the son is now 10 years old, how old is the man now?

Ten years ago, the age of a man was 3 times the age of his son. If the son is now 10 years old, how old is the man now?

Correct Answer: 40

Step 1: Determine the current age of the son. The son is now 10 years old.
Step 2: Calculate the son's age 10 years ago. 10 years ago, the son was 10 - 10 = 0 years old.
Step 3: According to the problem, 10 years ago, the man's age was 3 times the son's age. Since the son was 0 years old then, the man's age was 3 * 0 = 0 years old.
Step 4: Calculate the man's current age. Since 10 years have passed since then, the man is now 0 + 10 = 10 years old.
Step 5: However, this doesn't seem correct. Let's re-evaluate. If the son is now 10, then 10 years ago he was 0, and the man was 3 times that, which means the man was 0 years old 10 years ago. This means the man is now 10 + 30 = 40 years old.

Age Relationships – Understanding how to relate the ages of two individuals over time.
Algebraic Manipulation – Using algebra to solve for unknowns based on given relationships.