In 10 years, a father will be twice as old as his son. If the son is currently 10 years old, how old is the father now?

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Q: In 10 years, a father will be twice as old as his son. If the son is currently 10 years old, how old is the father now?

Solution: Let the father's current age be x. In 10 years, x + 10 = 2(10 + 10). Solving gives x = 30.

Steps: 8

Step 1: Identify the current age of the son. The son is currently 10 years old.
Step 2: Let the father's current age be represented by 'x'.
Step 3: In 10 years, the son's age will be 10 + 10 = 20 years old.
Step 4: In 10 years, the father's age will be x + 10.
Step 5: According to the problem, in 10 years, the father will be twice as old as the son. This can be written as: x + 10 = 2 * (10 + 10).
Step 6: Simplify the equation: x + 10 = 2 * 20, which means x + 10 = 40.
Step 7: To find 'x', subtract 10 from both sides: x = 40 - 10.
Step 8: Calculate the result: x = 30. This means the father is currently 30 years old.