A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What

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Question: A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?

Options:

Correct Answer: 17.32 Nm

Solution:

Torque = Force × Distance × sin(60°) = 10 N × 2 m × (√3/2) = 17.32 Nm.

A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?

A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?

Step 1: Identify the force applied, which is 10 N.
Step 2: Identify the distance from the pivot to where the force is applied, which is 2 m.
Step 3: Identify the angle at which the force is applied, which is 60 degrees.
Step 4: Use the formula for torque: Torque = Force × Distance × sin(angle).
Step 5: Substitute the values into the formula: Torque = 10 N × 2 m × sin(60°).
Step 6: Calculate sin(60°), which is √3/2 or approximately 0.866.
Step 7: Multiply the values: Torque = 10 N × 2 m × (√3/2).
Step 8: Calculate the result: Torque = 10 × 2 × (√3/2) = 10 × √3 = 17.32 Nm.

Torque Calculation – Torque is calculated as the product of the force applied, the distance from the pivot point, and the sine of the angle between the force and the lever arm.
Trigonometric Functions – Understanding how to apply the sine function to find the effective component of the force that contributes to torque.