A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What

Practice Questions

Q1
A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?
  1. 10 Nm
  2. 17.32 Nm
  3. 20 Nm
  4. 5 Nm

Questions & Step-by-Step Solutions

A force of 10 N is applied at an angle of 60 degrees to a lever arm of 2 m. What is the torque about the pivot?
  • Step 1: Identify the force applied, which is 10 N.
  • Step 2: Identify the distance from the pivot to where the force is applied, which is 2 m.
  • Step 3: Identify the angle at which the force is applied, which is 60 degrees.
  • Step 4: Use the formula for torque: Torque = Force × Distance × sin(angle).
  • Step 5: Substitute the values into the formula: Torque = 10 N × 2 m × sin(60°).
  • Step 6: Calculate sin(60°), which is √3/2 or approximately 0.866.
  • Step 7: Multiply the values: Torque = 10 N × 2 m × (√3/2).
  • Step 8: Calculate the result: Torque = 10 × 2 × (√3/2) = 10 × √3 = 17.32 Nm.
  • Torque Calculation – Torque is calculated as the product of the force applied, the distance from the pivot point, and the sine of the angle between the force and the lever arm.
  • Trigonometric Functions – Understanding how to apply the sine function to find the effective component of the force that contributes to torque.
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