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If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from t

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Question: If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?

Options:

  1. 50 N
  2. 45 N
  3. 40 N
  4. 30 N

Correct Answer: 50 N

Solution: 

Force = Torque / Distance = 15 Nm / 0.3 m = 50 N.

If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from t

Practice Questions

Q1
If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
  1. 50 N
  2. 45 N
  3. 40 N
  4. 30 N

Questions & Step-by-Step Solutions

If a torque of 15 Nm is produced by a force acting at a distance of 0.3 m from the pivot, what is the magnitude of the force?
  • Step 1: Understand that torque is calculated using the formula: Torque = Force x Distance.
  • Step 2: Rearrange the formula to find Force: Force = Torque / Distance.
  • Step 3: Substitute the given values into the formula: Torque = 15 Nm and Distance = 0.3 m.
  • Step 4: Calculate the Force: Force = 15 Nm / 0.3 m.
  • Step 5: Perform the division: 15 divided by 0.3 equals 50.
  • Step 6: Conclude that the magnitude of the force is 50 N.
  • Torque Calculation – Understanding the relationship between torque, force, and distance from the pivot point, where Torque = Force x Distance.
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