Question: If a rolling object has a radius of R and rolls with a speed v, what is its kinetic energy?
Options:
Correct Answer: (1/2)mv^2 + (1/2)(1/2)mR^2(v/R)^2
Solution:
The total kinetic energy of a rolling object is the sum of translational and rotational kinetic energy, which simplifies to (1/2)mv^2 + (1/4)mv^2 = (3/4)mv^2.