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A solid sphere of radius R rolls without slipping down an inclined plane of angl

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Question: A solid sphere of radius R rolls without slipping down an inclined plane of angle θ. What is the acceleration of the center of mass of the sphere?

Options:

  1. g sin(θ)
  2. g sin(θ)/2
  3. g sin(θ)/3
  4. g sin(θ)/4

Correct Answer: g sin(θ)

Solution: 

The acceleration of the center of mass of a solid sphere rolling down an incline is given by a = g sin(θ) / (1 + (2/5)) = g sin(θ) / (7/5) = (5/7) g sin(θ).

A solid sphere of radius R rolls without slipping down an inclined plane of angl

Practice Questions

Q1
A solid sphere of radius R rolls without slipping down an inclined plane of angle θ. What is the acceleration of the center of mass of the sphere?
  1. g sin(θ)
  2. g sin(θ)/2
  3. g sin(θ)/3
  4. g sin(θ)/4

Questions & Step-by-Step Solutions

A solid sphere of radius R rolls without slipping down an inclined plane of angle θ. What is the acceleration of the center of mass of the sphere?
  • Step 1: Identify the forces acting on the sphere. The main force is gravity, which can be broken down into two components: one parallel to the incline (down the slope) and one perpendicular to the incline (normal force).
  • Step 2: Calculate the gravitational force component acting down the incline. This is given by F_parallel = m * g * sin(θ), where m is the mass of the sphere and g is the acceleration due to gravity.
  • Step 3: Understand that the sphere rolls without slipping. This means that as it rolls, it also rotates. The moment of inertia (I) for a solid sphere is I = (2/5) * m * R^2.
  • Step 4: Apply Newton's second law for rotation. The torque (τ) caused by the gravitational force is τ = F_parallel * R = (m * g * sin(θ)) * R.
  • Step 5: Relate torque to angular acceleration (α) using τ = I * α. Substitute I from Step 3: (m * g * sin(θ)) * R = (2/5) * m * R^2 * α.
  • Step 6: Solve for angular acceleration (α). Rearranging gives α = (5/2) * (g * sin(θ) / R).
  • Step 7: Relate linear acceleration (a) of the center of mass to angular acceleration (α) using the relationship a = R * α. Substitute α from Step 6: a = R * ((5/2) * (g * sin(θ) / R)).
  • Step 8: Simplify the expression for linear acceleration. This gives a = (5/2) * g * sin(θ).
  • Step 9: Adjust for the rolling condition. The effective acceleration of the center of mass is a = (5/7) * g * sin(θ) after considering the rolling without slipping condition.
  • Rolling Motion – Understanding the dynamics of a solid sphere rolling down an incline, including the relationship between translational and rotational motion.
  • Moment of Inertia – Applying the moment of inertia for a solid sphere (I = (2/5) m R^2) to determine the acceleration of the center of mass.
  • Inclined Plane Dynamics – Analyzing forces acting on an object on an incline, including gravitational force components and friction.
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