Two particles of masses m1 and m2 are moving in a straight line with velocities

Practice Questions

Two particles of masses m1 and m2 are moving in a straight line with velocities v1 and v2 respectively. If they collide elastically, what is the expression for the change in angular momentum about the center of mass?

m1v1 + m2v2
m1v1 - m2v2
0
m1v1 + m2v2 - (m1v1' + m2v2')

Questions & Step-by-Step Solutions

Step 1: Understand that angular momentum is a measure of the rotational motion of an object around a point, in this case, the center of mass.
Step 2: Recall that in an elastic collision, both momentum and kinetic energy are conserved.
Step 3: Identify the center of mass (CM) of the two particles. The position of the CM can be calculated using the formula: CM = (m1 * x1 + m2 * x2) / (m1 + m2), where x1 and x2 are the positions of the particles.
Step 4: Calculate the initial angular momentum about the center of mass before the collision using the formula: L_initial = m1 * v1 * r1 + m2 * v2 * r2, where r1 and r2 are the distances from the center of mass to each particle.
Step 5: After the collision, calculate the final angular momentum using the new velocities of the particles, which can be found using the conservation of momentum and kinetic energy.
Step 6: The change in angular momentum is found by subtracting the initial angular momentum from the final angular momentum: Change in L = L_final - L_initial.
Step 7: Since angular momentum is conserved in an elastic collision, the change in angular momentum about the center of mass is zero.

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Two particles of masses m1 and m2 are moving in a straight line with velocities

Practice Questions

Questions & Step-by-Step Solutions

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