A mass attached to a spring oscillates with a period of 2 seconds. What is the a
Practice Questions
Q1
A mass attached to a spring oscillates with a period of 2 seconds. What is the angular frequency of the motion?
0.5 rad/s
1 rad/s
3.14 rad/s
6.28 rad/s
Questions & Step-by-Step Solutions
A mass attached to a spring oscillates with a period of 2 seconds. What is the angular frequency of the motion?
Step 1: Understand that the period (T) is the time it takes for one complete cycle of motion. In this case, T = 2 seconds.
Step 2: Know the formula to find angular frequency (ω), which is ω = 2π/T.
Step 3: Substitute the value of T into the formula: ω = 2π/2.
Step 4: Simplify the equation: ω = π rad/s.
Step 5: If needed, you can approximate π as 3.14, so ω ≈ 3.14 rad/s.
Oscillatory Motion – The motion of an object that moves back and forth around an equilibrium position, characterized by a period and angular frequency.
Angular Frequency – A measure of how quickly an object oscillates, calculated as ω = 2π/T, where T is the period of the motion.
Period – The time taken for one complete cycle of oscillation, which is inversely related to the frequency and angular frequency.
