In a single-slit diffraction pattern, what is the angular width of the central m
Practice Questions
Q1
In a single-slit diffraction pattern, what is the angular width of the central maximum if the slit width is 0.5 mm and the wavelength of light is 500 nm?
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Questions & Step-by-Step Solutions
In a single-slit diffraction pattern, what is the angular width of the central maximum if the slit width is 0.5 mm and the wavelength of light is 500 nm?
Step 1: Identify the formula for the angular width of the central maximum in a single-slit diffraction pattern, which is given by Angular width = 2λ/a.
Step 2: Note the values provided in the question: the slit width (a) is 0.5 mm and the wavelength of light (λ) is 500 nm.
Step 3: Convert the slit width from millimeters to micrometers for easier calculation: 0.5 mm = 500 μm.
Step 4: Convert the wavelength from nanometers to micrometers: 500 nm = 0.5 μm.
Step 5: Substitute the values into the formula: Angular width = 2 * (0.5 μm) / (500 μm).
