If the refractive index of a medium is 1.33, what is the critical angle for tota

Practice Questions

Q1
If the refractive index of a medium is 1.33, what is the critical angle for total internal reflection?
  1. 48.6°
  2. 60.0°
  3. 30.0°
  4. 45.0°

Questions & Step-by-Step Solutions

If the refractive index of a medium is 1.33, what is the critical angle for total internal reflection?
  • Step 1: Understand that the critical angle is the angle of incidence above which total internal reflection occurs.
  • Step 2: Know that the formula to find the critical angle (θc) is θc = sin⁻¹(1/n), where n is the refractive index of the medium.
  • Step 3: In this case, the refractive index (n) is given as 1.33.
  • Step 4: Substitute the value of n into the formula: θc = sin⁻¹(1/1.33).
  • Step 5: Calculate 1/1.33, which is approximately 0.7519.
  • Step 6: Use a calculator to find the inverse sine (sin⁻¹) of 0.7519.
  • Step 7: The result will give you the critical angle, which is approximately 48.6°.
  • Refractive Index – The refractive index is a measure of how much light slows down in a medium compared to vacuum.
  • Critical Angle – The critical angle is the angle of incidence above which total internal reflection occurs when light travels from a denser to a less dense medium.
  • Total Internal Reflection – Total internal reflection is the phenomenon where light is completely reflected back into a medium when it hits the boundary at an angle greater than the critical angle.
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