A beam of light passes from diamond (n=2.42) to air. What is the critical angle?

Practice Questions

Q1
A beam of light passes from diamond (n=2.42) to air. What is the critical angle?
  1. 24.4°
  2. 30.0°
  3. 36.9°
  4. 42.0°

Questions & Step-by-Step Solutions

A beam of light passes from diamond (n=2.42) to air. What is the critical angle?
  • Step 1: Understand that the critical angle is the angle of incidence above which light cannot pass through a boundary and is instead reflected back.
  • Step 2: Identify the refractive indices of the two materials involved. Here, diamond has a refractive index (n1) of 2.42 and air has a refractive index (n2) of approximately 1.
  • Step 3: Use the formula for the critical angle (θc): θc = sin⁻¹(n2/n1).
  • Step 4: Substitute the values into the formula: θc = sin⁻¹(1/2.42).
  • Step 5: Calculate the value: θc ≈ sin⁻¹(0.4132).
  • Step 6: Use a calculator to find the inverse sine: θc ≈ 24.4°.
  • Refraction and Critical Angle – The critical angle is the angle of incidence above which total internal reflection occurs when light passes from a denser medium to a less dense medium.
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