What is the magnification produced by a concave mirror if the object is placed at a distance of 15 cm and the image is formed at 5 cm?
Practice Questions
1 question
Q1
What is the magnification produced by a concave mirror if the object is placed at a distance of 15 cm and the image is formed at 5 cm?
1/3
1/2
3
2
Magnification (m) = -v/u = -(-5)/(-15) = 1/3. Therefore, the magnification is 3.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the magnification produced by a concave mirror if the object is placed at a distance of 15 cm and the image is formed at 5 cm?
Solution: Magnification (m) = -v/u = -(-5)/(-15) = 1/3. Therefore, the magnification is 3.
Steps: 6
Step 1: Identify the given values. The object distance (u) is -15 cm (negative because it is in front of the mirror) and the image distance (v) is -5 cm (also negative because the image is real and formed in front of the mirror).
Step 2: Use the magnification formula, which is m = -v/u.
Step 3: Substitute the values into the formula: m = -(-5)/(-15).
Step 4: Simplify the equation: m = 5/15.
Step 5: Reduce the fraction: m = 1/3.
Step 6: Interpret the result. The magnification is 1/3, which means the image is smaller than the object.
