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A's age is twice that of B's age. If the difference between their ages is 10 yea
A's age is twice that of B's age. If the difference between their ages is 10 years, what is A's age?
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Q1
A's age is twice that of B's age. If the difference between their ages is 10 years, what is A's age?
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Let B's age be x. Then A's age is 2x. The difference is 2x - x = 10, hence x = 10. So, A's age is 2 * 10 = 20.
Questions & Step-by-step Solutions
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Q: A's age is twice that of B's age. If the difference between their ages is 10 years, what is A's age?
Solution:
Let B's age be x. Then A's age is 2x. The difference is 2x - x = 10, hence x = 10. So, A's age is 2 * 10 = 20.
Steps: 8
Show Steps
Step 1: Let B's age be represented by the variable x.
Step 2: Since A's age is twice B's age, we can express A's age as 2x.
Step 3: The problem states that the difference between A's age and B's age is 10 years.
Step 4: We can write the equation for the difference: A's age - B's age = 10, which translates to 2x - x = 10.
Step 5: Simplify the equation: 2x - x equals x, so we have x = 10.
Step 6: Now that we know B's age (x) is 10, we can find A's age by calculating 2 * x.
Step 7: Calculate A's age: 2 * 10 = 20.
Step 8: Therefore, A's age is 20 years.
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