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A diverging lens has a focal length of -10 cm. What is the image distance when t
A diverging lens has a focal length of -10 cm. What is the image distance when the object is placed at 5 cm?
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Practice Questions
1 question
Q1
A diverging lens has a focal length of -10 cm. What is the image distance when the object is placed at 5 cm?
-3.33 cm
-5 cm
3.33 cm
5 cm
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Using the lens formula 1/f = 1/v - 1/u, we have 1/(-10) = 1/v - 1/5. Solving gives v = -3.33 cm.
Questions & Step-by-step Solutions
1 item
Q
Q: A diverging lens has a focal length of -10 cm. What is the image distance when the object is placed at 5 cm?
Solution:
Using the lens formula 1/f = 1/v - 1/u, we have 1/(-10) = 1/v - 1/5. Solving gives v = -3.33 cm.
Steps: 8
Show Steps
Step 1: Identify the given values. The focal length (f) of the diverging lens is -10 cm, and the object distance (u) is 5 cm.
Step 2: Write down the lens formula: 1/f = 1/v - 1/u.
Step 3: Substitute the known values into the lens formula: 1/(-10) = 1/v - 1/5.
Step 4: Simplify the equation: -0.1 = 1/v - 0.2.
Step 5: Rearrange the equation to isolate 1/v: 1/v = -0.1 + 0.2.
Step 6: Calculate the right side: 1/v = 0.1.
Step 7: Take the reciprocal to find v: v = 1/0.1 = 10 cm.
Step 8: Since the lens is diverging, the image distance (v) will be negative, so v = -10 cm.
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