If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
Practice Questions
1 question
Q1
If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
0.12 m
0.24 m
0.36 m
0.48 m
Fringe separation (β) = λD/d. β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m. Distance between first and second bright fringes = 2β = 0.024 m.
Questions & Step-by-step Solutions
1 item
Q
Q: If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
Solution: Fringe separation (β) = λD/d. β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m. Distance between first and second bright fringes = 2β = 0.024 m.
Steps: 5
Step 1: Identify the given values from the problem. Wavelength (λ) = 600 nm, which is 600 x 10^-9 m. Distance between the slits (d) = 0.1 mm, which is 0.1 x 10^-3 m or 0.0001 m. Distance to the screen (D) = 2 m.
Step 2: Use the formula for fringe separation (β) which is β = (λD) / d.
Step 3: Substitute the values into the formula: β = (600 x 10^-9 m * 2 m) / 0.0001 m.
Step 4: Calculate the value of β: β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m.
Step 5: To find the distance between the first and second bright fringes, multiply β by 2: Distance = 2β = 2 * 0.012 m = 0.024 m.
