If the wavelength of light used in Young's experiment is 600 nm and the distance
Practice Questions
Q1
If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
0.12 m
0.24 m
0.36 m
0.48 m
Questions & Step-by-Step Solutions
If the wavelength of light used in Young's experiment is 600 nm and the distance between the slits is 0.1 mm, what is the distance between the first and second bright fringes on a screen 2 m away?
Step 1: Identify the given values from the problem. Wavelength (λ) = 600 nm, which is 600 x 10^-9 m. Distance between the slits (d) = 0.1 mm, which is 0.1 x 10^-3 m or 0.0001 m. Distance to the screen (D) = 2 m.
Step 2: Use the formula for fringe separation (β) which is β = (λD) / d.
Step 3: Substitute the values into the formula: β = (600 x 10^-9 m * 2 m) / 0.0001 m.
Step 4: Calculate the value of β: β = (600 x 10^-9 * 2) / 0.0001 = 0.012 m.
Step 5: To find the distance between the first and second bright fringes, multiply β by 2: Distance = 2β = 2 * 0.012 m = 0.024 m.
Young's Double Slit Experiment – This experiment demonstrates the wave nature of light through interference patterns created by two slits.
Fringe Separation Calculation – The formula β = λD/d is used to calculate the distance between bright fringes in an interference pattern.
Units and Conversions – Understanding the conversion of units (e.g., nm to m, mm to m) is crucial for accurate calculations.
