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A and B are of different ages. If A is 5 years older than B and the sum of their
A and B are of different ages. If A is 5 years older than B and the sum of their ages is 45, how old is A?
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Practice Questions
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Q1
A and B are of different ages. If A is 5 years older than B and the sum of their ages is 45, how old is A?
20
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25
27
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Let B's age be x. Then A's age is x + 5. So, x + (x + 5) = 45. Solving gives A = 25.
Questions & Step-by-step Solutions
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Q
Q: A and B are of different ages. If A is 5 years older than B and the sum of their ages is 45, how old is A?
Solution:
Let B's age be x. Then A's age is x + 5. So, x + (x + 5) = 45. Solving gives A = 25.
Steps: 8
Show Steps
Step 1: Let B's age be represented by the variable x.
Step 2: Since A is 5 years older than B, we can express A's age as x + 5.
Step 3: The problem states that the sum of A's age and B's age is 45. We can write this as: x + (x + 5) = 45.
Step 4: Simplify the equation: Combine like terms to get 2x + 5 = 45.
Step 5: Subtract 5 from both sides of the equation: 2x = 40.
Step 6: Divide both sides by 2 to find x: x = 20. This means B is 20 years old.
Step 7: Now, to find A's age, substitute x back into the equation for A: A = x + 5 = 20 + 5.
Step 8: Therefore, A's age is 25.
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