A mother is 4 times as old as her daughter. After 8 years, the mother will be twice as old as her daughter. What is the present age of the daughter?
Practice Questions
1 question
Q1
A mother is 4 times as old as her daughter. After 8 years, the mother will be twice as old as her daughter. What is the present age of the daughter?
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8
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Let the daughter's age be x. Then the mother's age is 4x. In 8 years, 4x + 8 = 2(x + 8). Solving gives x = 8.
Questions & Step-by-step Solutions
1 item
Q
Q: A mother is 4 times as old as her daughter. After 8 years, the mother will be twice as old as her daughter. What is the present age of the daughter?
Solution: Let the daughter's age be x. Then the mother's age is 4x. In 8 years, 4x + 8 = 2(x + 8). Solving gives x = 8.
Steps: 10
Step 1: Let the daughter's current age be represented by 'x'.
Step 2: Since the mother is 4 times as old as her daughter, we can express the mother's age as '4x'.
Step 3: In 8 years, the daughter's age will be 'x + 8'.
Step 4: In 8 years, the mother's age will be '4x + 8'.
Step 5: According to the problem, in 8 years, the mother will be twice as old as the daughter. We can write this as the equation: '4x + 8 = 2(x + 8)'.
