What is the magnetic field strength at the center of a square loop of side a carrying a current I?
Practice Questions
1 question
Q1
What is the magnetic field strength at the center of a square loop of side a carrying a current I?
(μ₀I)/(2a)
(μ₀I)/(4a)
(μ₀I)/(√2a)
(μ₀I)/(8a)
The magnetic field at the center of a square loop is given by B = (μ₀I)/(√2a).
Questions & Step-by-step Solutions
1 item
Q
Q: What is the magnetic field strength at the center of a square loop of side a carrying a current I?
Solution: The magnetic field at the center of a square loop is given by B = (μ₀I)/(√2a).
Steps: 6
Step 1: Understand that a square loop is a shape with four equal sides, and we are interested in the magnetic field at its center.
Step 2: Recognize that the current I flowing through the loop creates a magnetic field around it.
Step 3: Recall that the magnetic field strength at the center of a loop can be calculated using a specific formula.
Step 4: The formula for the magnetic field B at the center of a square loop is B = (μ₀I)/(√2a), where μ₀ is the permeability of free space, I is the current, and a is the length of one side of the square.
Step 5: Identify that √2 is a mathematical constant that comes from the geometry of the square loop.
Step 6: Substitute the values of μ₀, I, and a into the formula to find the magnetic field strength.
