If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?
Practice Questions
1 question
Q1
If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?
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Let the number of years be x. In x years, the father's age will be 45 + x and the son's age will be 15 + x. The equation is 45 + x = 2(15 + x), which simplifies to 45 + x = 30 + 2x, so x = 15.
Questions & Step-by-step Solutions
1 item
Q
Q: If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?
Solution: Let the number of years be x. In x years, the father's age will be 45 + x and the son's age will be 15 + x. The equation is 45 + x = 2(15 + x), which simplifies to 45 + x = 30 + 2x, so x = 15.
Steps: 9
Step 1: Identify the current ages of the father and son. The father is 45 years old and the son is 15 years old.
Step 2: Define the number of years in the future we are trying to find as 'x'.
Step 3: Write the father's age in 'x' years. It will be 45 + x.
Step 4: Write the son's age in 'x' years. It will be 15 + x.
Step 5: Set up the equation to find when the father's age will be twice the son's age: 45 + x = 2(15 + x).
Step 6: Simplify the equation: 45 + x = 30 + 2x.
Step 7: Rearrange the equation to isolate 'x': 45 - 30 = 2x - x.
Step 8: Simplify further: 15 = x.
Step 9: Conclude that in 15 years, the father will be twice as old as the son.
