If the present age of a father is 45 years and his son is 15 years old, in how m

Practice Questions

Q1
If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?
  1. 10
  2. 15
  3. 20
  4. 5

Questions & Step-by-Step Solutions

If the present age of a father is 45 years and his son is 15 years old, in how many years will the father be twice as old as his son?
Correct Answer: 15
  • Step 1: Identify the current ages of the father and son. The father is 45 years old and the son is 15 years old.
  • Step 2: Define the number of years in the future we are trying to find as 'x'.
  • Step 3: Write the father's age in 'x' years. It will be 45 + x.
  • Step 4: Write the son's age in 'x' years. It will be 15 + x.
  • Step 5: Set up the equation to find when the father's age will be twice the son's age: 45 + x = 2(15 + x).
  • Step 6: Simplify the equation: 45 + x = 30 + 2x.
  • Step 7: Rearrange the equation to isolate 'x': 45 - 30 = 2x - x.
  • Step 8: Simplify further: 15 = x.
  • Step 9: Conclude that in 15 years, the father will be twice as old as the son.
  • Age Problems – This question tests the ability to set up and solve equations based on the ages of individuals over time.
  • Algebraic Manipulation – It requires skills in manipulating algebraic expressions to isolate variables and solve for unknowns.
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