A solenoid of length L and cross-sectional area A carries a current I. What is t

Practice Questions

Q1
A solenoid of length L and cross-sectional area A carries a current I. What is the magnetic field inside the solenoid?
  1. μ₀nI
  2. μ₀I/n
  3. μ₀I/(nA)
  4. μ₀I/(2n)

Questions & Step-by-Step Solutions

A solenoid of length L and cross-sectional area A carries a current I. What is the magnetic field inside the solenoid?
  • Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
  • Step 2: Identify the key variables: L is the length of the solenoid, A is the cross-sectional area, and I is the current flowing through the solenoid.
  • Step 3: Know that the magnetic field inside a solenoid depends on the number of turns of wire per unit length (n) and the current (I).
  • Step 4: Calculate n, the number of turns per unit length, by dividing the total number of turns (N) by the length (L) of the solenoid: n = N / L.
  • Step 5: Use the formula for the magnetic field inside the solenoid: B = μ₀nI, where μ₀ is the permeability of free space (a constant).
  • Step 6: Substitute the value of n from Step 4 into the formula to find the magnetic field B.
  • Magnetic Field in Solenoids – The magnetic field inside a solenoid is determined by the current flowing through it and the number of turns per unit length.
  • Understanding Variables – Recognizing the significance of each variable in the formula B = μ₀nI, including the permeability of free space (μ₀), the number of turns per unit length (n), and the current (I).
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