A solenoid of length L and cross-sectional area A carries a current I. What is t

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Question: A solenoid of length L and cross-sectional area A carries a current I. What is the magnetic field inside the solenoid?

Options:

Correct Answer: μ₀nI

Solution:

The magnetic field inside a solenoid is given by B = μ₀nI, where n is the number of turns per unit length.

A solenoid of length L and cross-sectional area A carries a current I. What is the magnetic field inside the solenoid?

A solenoid of length L and cross-sectional area A carries a current I. What is the magnetic field inside the solenoid?

Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
Step 2: Identify the key variables: L is the length of the solenoid, A is the cross-sectional area, and I is the current flowing through the solenoid.
Step 3: Know that the magnetic field inside a solenoid depends on the number of turns of wire per unit length (n) and the current (I).
Step 4: Calculate n, the number of turns per unit length, by dividing the total number of turns (N) by the length (L) of the solenoid: n = N / L.
Step 5: Use the formula for the magnetic field inside the solenoid: B = μ₀nI, where μ₀ is the permeability of free space (a constant).
Step 6: Substitute the value of n from Step 4 into the formula to find the magnetic field B.

Magnetic Field in Solenoids – The magnetic field inside a solenoid is determined by the current flowing through it and the number of turns per unit length.
Understanding Variables – Recognizing the significance of each variable in the formula B = μ₀nI, including the permeability of free space (μ₀), the number of turns per unit length (n), and the current (I).