For a solenoid of length L and n turns per unit length carrying current I, what
Practice Questions
Q1
For a solenoid of length L and n turns per unit length carrying current I, what is the magnetic field inside the solenoid?
μ₀nI
μ₀I/n
μ₀I/L
μ₀nI/L
Questions & Step-by-Step Solutions
For a solenoid of length L and n turns per unit length carrying current I, what is the magnetic field inside the solenoid?
Step 1: Understand what a solenoid is. A solenoid is a coil of wire that creates a magnetic field when an electric current passes through it.
Step 2: Identify the key components of the solenoid: its length (L), the number of turns per unit length (n), and the current (I) flowing through it.
Step 3: Recognize that the magnetic field (B) inside a solenoid can be calculated using a specific formula.
Step 4: The formula for the magnetic field inside a solenoid is B = μ₀nI, where μ₀ is the permeability of free space (a constant).
Step 5: Plug in the values of n (turns per unit length) and I (current) into the formula to find the magnetic field B.
Magnetic Field in a Solenoid – The magnetic field inside a long solenoid is uniform and is determined by the product of the permeability of free space (μ₀), the number of turns per unit length (n), and the current (I) flowing through the solenoid.
