What is the impedance of a series circuit containing a resistor (R) and an inductor (L)?
Practice Questions
1 question
Q1
What is the impedance of a series circuit containing a resistor (R) and an inductor (L)?
R
√(R^2 + (ωL)^2)
R + ωL
R - ωL
The impedance Z = √(R^2 + (ωL)^2) in a series R-L circuit.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the impedance of a series circuit containing a resistor (R) and an inductor (L)?
Solution: The impedance Z = √(R^2 + (ωL)^2) in a series R-L circuit.
Steps: 7
Step 1: Understand that impedance (Z) is a measure of how much a circuit resists the flow of electric current.
Step 2: Identify the components in the circuit: a resistor (R) and an inductor (L).
Step 3: Recognize that in a series circuit, the total impedance is affected by both the resistor and the inductor.
Step 4: Know that the impedance of the resistor is simply R.
Step 5: Understand that the impedance of the inductor is given by the formula ωL, where ω (omega) is the angular frequency of the AC signal.
Step 6: Combine the effects of the resistor and inductor using the formula for total impedance in a series circuit: Z = √(R^2 + (ωL)^2).
Step 7: This formula shows that you take the square of the resistance (R), the square of the inductive reactance (ωL), add them together, and then take the square root to find the total impedance.
