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The age of a father is twice the age of his son. If the sum of their ages is 60
The age of a father is twice the age of his son. If the sum of their ages is 60 years, how old is the son?
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Q1
The age of a father is twice the age of his son. If the sum of their ages is 60 years, how old is the son?
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Let the son's age be x. Then the father's age is 2x. The equation is x + 2x = 60, which simplifies to 3x = 60, so x = 20.
Questions & Step-by-step Solutions
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Q: The age of a father is twice the age of his son. If the sum of their ages is 60 years, how old is the son?
Solution:
Let the son's age be x. Then the father's age is 2x. The equation is x + 2x = 60, which simplifies to 3x = 60, so x = 20.
Steps: 7
Show Steps
Step 1: Let the son's age be represented by the variable x.
Step 2: Since the father's age is twice the son's age, we can represent the father's age as 2x.
Step 3: According to the problem, the sum of their ages is 60 years. We can write this as an equation: x + 2x = 60.
Step 4: Combine the terms on the left side of the equation: 3x = 60.
Step 5: To find the value of x (the son's age), divide both sides of the equation by 3: x = 60 / 3.
Step 6: Calculate the result: x = 20.
Step 7: Therefore, the son is 20 years old.
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