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If the present age of a woman is 5 years more than twice the age of her son, and
If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
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Q1
If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
25
30
20
35
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The son's age is 10. Therefore, the woman's age is 2 * 10 + 5 = 20 + 5 = 25.
Questions & Step-by-step Solutions
1 item
Q
Q: If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
Solution:
The son's age is 10. Therefore, the woman's age is 2 * 10 + 5 = 20 + 5 = 25.
Steps: 5
Show Steps
Step 1: Identify the son's current age, which is given as 10 years.
Step 2: Understand the relationship between the woman's age and the son's age. The woman's age is 5 years more than twice the son's age.
Step 3: Calculate twice the son's age. Since the son is 10 years old, twice his age is 2 * 10 = 20.
Step 4: Add 5 years to the result from Step 3 to find the woman's age. So, 20 + 5 = 25.
Step 5: Conclude that the woman's age is 25 years.
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