If the present age of a woman is 5 years more than twice the age of her son, and
Practice Questions
Q1
If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
25
30
20
35
Questions & Step-by-Step Solutions
If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
Correct Answer: 25
Step 1: Identify the son's current age, which is given as 10 years.
Step 2: Understand the relationship between the woman's age and the son's age. The woman's age is 5 years more than twice the son's age.
Step 3: Calculate twice the son's age. Since the son is 10 years old, twice his age is 2 * 10 = 20.
Step 4: Add 5 years to the result from Step 3 to find the woman's age. So, 20 + 5 = 25.
Step 5: Conclude that the woman's age is 25 years.
Algebraic Expressions – The question involves forming and solving a simple algebraic expression based on the relationship between the ages of the woman and her son.
Age Problems – This is a typical age problem where the relationship between two people's ages is used to find one of their ages.
