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If the present age of a woman is 5 years more than twice the age of her son, and

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Question: If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?

Options:

  1. 25
  2. 30
  3. 20
  4. 35

Correct Answer: 25

Solution: 

The son\'s age is 10. Therefore, the woman\'s age is 2 * 10 + 5 = 20 + 5 = 25.

If the present age of a woman is 5 years more than twice the age of her son, and

Practice Questions

Q1
If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
  1. 25
  2. 30
  3. 20
  4. 35

Questions & Step-by-Step Solutions

If the present age of a woman is 5 years more than twice the age of her son, and the son is currently 10 years old, what is the age of the woman?
Correct Answer: 25
  • Step 1: Identify the son's current age, which is given as 10 years.
  • Step 2: Understand the relationship between the woman's age and the son's age. The woman's age is 5 years more than twice the son's age.
  • Step 3: Calculate twice the son's age. Since the son is 10 years old, twice his age is 2 * 10 = 20.
  • Step 4: Add 5 years to the result from Step 3 to find the woman's age. So, 20 + 5 = 25.
  • Step 5: Conclude that the woman's age is 25 years.
  • Algebraic Expressions – The question involves forming and solving a simple algebraic expression based on the relationship between the ages of the woman and her son.
  • Age Problems – This is a typical age problem where the relationship between two people's ages is used to find one of their ages.
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