Question: If the temperature of a gas is increased from 200 K to 800 K, how does the RMS speed change?
Options:
Increases by 2
Increases by 4
Increases by sqrt(4)
Decreases by sqrt(4)
Correct Answer: Increases by sqrt(4)
Solution:
RMS speed increases by sqrt(4) = 2, since v_rms is proportional to sqrt(T).
If the temperature of a gas is increased from 200 K to 800 K, how does the RMS s
Practice Questions
Q1
If the temperature of a gas is increased from 200 K to 800 K, how does the RMS speed change?
Increases by 2
Increases by 4
Increases by sqrt(4)
Decreases by sqrt(4)
Questions & Step-by-Step Solutions
If the temperature of a gas is increased from 200 K to 800 K, how does the RMS speed change?
Step 1: Understand that RMS speed (v_rms) of a gas is related to its temperature (T).
Step 2: Know the formula that relates RMS speed to temperature: v_rms is proportional to the square root of temperature (v_rms β βT).
Step 3: Identify the initial temperature (T1) as 200 K and the final temperature (T2) as 800 K.
Step 4: Calculate the ratio of the final temperature to the initial temperature: T2 / T1 = 800 K / 200 K = 4.
Step 5: Since v_rms is proportional to the square root of temperature, find the square root of the ratio: β(T2 / T1) = β4 = 2.
Step 6: Conclude that the RMS speed increases by a factor of 2 when the temperature increases from 200 K to 800 K.
RMS Speed and Temperature Relationship β The root mean square (RMS) speed of a gas is directly proportional to the square root of its absolute temperature (T), as described by the equation v_rms β βT.
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