Ten years ago, a man was twice as old as his son. If the man is currently 40 years old, how old is his son now?
Practice Questions
1 question
Q1
Ten years ago, a man was twice as old as his son. If the man is currently 40 years old, how old is his son now?
15
20
10
25
Ten years ago, the man was 30 years old. If he was twice as old as his son then, the son was 30 / 2 = 15 years old. Now, the son is 15 + 10 = 25 years old.
Questions & Step-by-step Solutions
1 item
Q
Q: Ten years ago, a man was twice as old as his son. If the man is currently 40 years old, how old is his son now?
Solution: Ten years ago, the man was 30 years old. If he was twice as old as his son then, the son was 30 / 2 = 15 years old. Now, the son is 15 + 10 = 25 years old.
Steps: 5
Step 1: Determine the man's age ten years ago. Since he is currently 40 years old, ten years ago he was 40 - 10 = 30 years old.
Step 2: Understand that ten years ago, the man was twice as old as his son. This means if we let the son's age ten years ago be 'x', then the man's age was 2x.
Step 3: Set up the equation based on the information: 2x = 30 (the man's age ten years ago).
Step 4: Solve for 'x' by dividing both sides of the equation by 2: x = 30 / 2 = 15. This means the son was 15 years old ten years ago.
Step 5: Calculate the son's current age by adding 10 years to his age ten years ago: 15 + 10 = 25. Therefore, the son is now 25 years old.
