If a gas occupies 10 L at 1 atm, what will be its volume at 2 atm if the tempera

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Question: If a gas occupies 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

Options:

Correct Answer: 5 L

Solution:

Using Boyle\'s Law (P1V1 = P2V2), if P1 = 1 atm, V1 = 10 L, and P2 = 2 atm, then V2 = (P1V1)/P2 = (1 atm * 10 L) / 2 atm = 5 L.

If a gas occupies 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

If a gas occupies 10 L at 1 atm, what will be its volume at 2 atm if the temperature remains constant?

Step 1: Identify the initial pressure (P1) and volume (V1) of the gas. Here, P1 = 1 atm and V1 = 10 L.
Step 2: Identify the final pressure (P2) of the gas. Here, P2 = 2 atm.
Step 3: Use Boyle's Law formula, which states that P1 * V1 = P2 * V2.
Step 4: Rearrange the formula to solve for the final volume (V2): V2 = (P1 * V1) / P2.
Step 5: Substitute the known values into the formula: V2 = (1 atm * 10 L) / 2 atm.
Step 6: Calculate the final volume: V2 = 10 L / 2 = 5 L.

Boyle's Law – Boyle's Law states that the pressure of a gas is inversely proportional to its volume when the temperature is held constant.