A projectile is launched with an initial speed of 50 m/s at an angle of 30 degre

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Question: A projectile is launched with an initial speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

Options:

Correct Answer: 43.3 m/s

Solution:

Horizontal component (vx) = u * cos(θ) = 50 * cos(30) = 50 * (√3/2) = 43.3 m/s.

A projectile is launched with an initial speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

A projectile is launched with an initial speed of 50 m/s at an angle of 30 degrees. What is the horizontal component of the velocity?

Step 1: Identify the initial speed of the projectile, which is given as 50 m/s.
Step 2: Identify the angle of launch, which is given as 30 degrees.
Step 3: Use the formula for the horizontal component of velocity, which is vx = u * cos(θ).
Step 4: Substitute the values into the formula: vx = 50 * cos(30).
Step 5: Calculate cos(30). The value of cos(30) is √3/2.
Step 6: Substitute cos(30) into the equation: vx = 50 * (√3/2).
Step 7: Calculate the result: vx = 50 * 0.866 (approximately), which equals 43.3 m/s.

Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
Trigonometry in Physics – Applying cosine to find the horizontal component of velocity based on the launch angle.