A projectile is launched with an initial velocity of 40 m/s at an angle of 45 de

Practice Questions

Q1
A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the time of flight?
  1. 4 s
  2. 5 s
  3. 6 s
  4. 7 s

Questions & Step-by-Step Solutions

A projectile is launched with an initial velocity of 40 m/s at an angle of 45 degrees. What is the time of flight?
  • Step 1: Identify the initial velocity (u) of the projectile, which is given as 40 m/s.
  • Step 2: Identify the angle of launch (θ), which is given as 45 degrees.
  • Step 3: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
  • Step 4: Calculate the sine of the angle θ. For 45 degrees, sin(45) is √2/2 or approximately 0.7071.
  • Step 5: Use the formula for time of flight (T) = (2 * u * sin(θ)) / g.
  • Step 6: Substitute the values into the formula: T = (2 * 40 * sin(45)) / 9.8.
  • Step 7: Calculate the numerator: 2 * 40 * 0.7071 = 56.568.
  • Step 8: Divide the result by g: 56.568 / 9.8 = 5.14 seconds.
  • Step 9: Conclude that the time of flight is approximately 5.14 seconds.
  • Projectile Motion – The motion of an object thrown into the air, subject to gravitational acceleration, characterized by its initial velocity, launch angle, and time of flight.
  • Trigonometric Functions – The use of sine and cosine functions to resolve the initial velocity into horizontal and vertical components.
  • Kinematic Equations – Equations that describe the motion of objects, including the relationship between time, velocity, and acceleration.
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