An object is thrown horizontally from the top of a 45 m high cliff. How far from

An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if the initial speed is 10 m/s?

An object is thrown horizontally from the top of a 45 m high cliff. How far from the base of the cliff will it land if the initial speed is 10 m/s?

Step 1: Identify the height of the cliff, which is 45 meters.
Step 2: Use the formula for time of flight, which is t = √(2h/g), where h is the height and g is the acceleration due to gravity (approximately 9.8 m/s²).
Step 3: Plug in the values: t = √(2 * 45 / 9.8).
Step 4: Calculate the value inside the square root: 2 * 45 = 90, then 90 / 9.8 ≈ 9.18.
Step 5: Take the square root of 9.18 to find the time of flight: t ≈ 3.03 seconds.
Step 6: Identify the initial horizontal speed of the object, which is 10 m/s.
Step 7: Use the formula for horizontal distance, which is distance = speed * time.
Step 8: Plug in the values: distance = 10 m/s * 3.03 s.
Step 9: Calculate the horizontal distance: 10 * 3.03 = 30.3 meters.

Projectile Motion – The question tests understanding of projectile motion, specifically the horizontal and vertical components of motion.
Time of Flight – Calculating the time an object takes to fall from a height using the formula derived from free fall equations.
Horizontal Distance Calculation – Determining the horizontal distance traveled using the initial horizontal speed and the time of flight.