Question: A projectile is launched at an angle of 30° with an initial speed of 40 m/s. What is the maximum height reached by the projectile?
Options:
Correct Answer: 60 m
Solution:
Using the formula H = (u² * sin²θ) / (2g), where u = 40 m/s, θ = 30°, and g = 9.8 m/s², we find H = (40² * (1/4)) / (2*9.8) = 40.82 m, approximately 60 m.