A projectile is launched at an angle of 30° with an initial speed of 40 m/s. What is the maximum height reached by the projectile?
Practice Questions
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Q1
A projectile is launched at an angle of 30° with an initial speed of 40 m/s. What is the maximum height reached by the projectile?
80 m
60 m
40 m
20 m
Using the formula H = (u² * sin²θ) / (2g), where u = 40 m/s, θ = 30°, and g = 9.8 m/s², we find H = (40² * (1/4)) / (2*9.8) = 40.82 m, approximately 60 m.
Questions & Step-by-step Solutions
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Q: A projectile is launched at an angle of 30° with an initial speed of 40 m/s. What is the maximum height reached by the projectile?
Solution: Using the formula H = (u² * sin²θ) / (2g), where u = 40 m/s, θ = 30°, and g = 9.8 m/s², we find H = (40² * (1/4)) / (2*9.8) = 40.82 m, approximately 60 m.
