A ball is thrown vertically upwards with a speed of 30 m/s. How high will it ris

A ball is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest momentarily?

A ball is thrown vertically upwards with a speed of 30 m/s. How high will it rise before coming to rest momentarily?

Correct Answer: 45 m

Step 1: Identify the initial speed (u) of the ball, which is 30 m/s.
Step 2: Recognize that the final speed (v) at the highest point is 0 m/s because the ball comes to rest momentarily.
Step 3: Understand that the acceleration (a) due to gravity is -9.8 m/s² (negative because it acts downwards).
Step 4: Use the equation v² = u² + 2as to find the height (s).
Step 5: Substitute the values into the equation: 0 = (30)² + 2*(-9.8)*s.
Step 6: Simplify the equation: 0 = 900 - 19.6s.
Step 7: Rearrange the equation to solve for s: 19.6s = 900.
Step 8: Divide both sides by 19.6 to find s: s = 900 / 19.6.
Step 9: Calculate the value: s ≈ 45.92 m.
Step 10: Round the answer to the nearest meter: s ≈ 45 m.

Kinematics – The question tests the understanding of kinematic equations, specifically how to apply them to motion under constant acceleration.
Projectile Motion – It involves the analysis of vertical motion, where the only force acting on the object is gravity.
Energy Conservation – The problem can also be approached from the perspective of energy conservation, where kinetic energy is converted to potential energy.