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What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000

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Question: What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)

Options:

  1. 4500 V
  2. 1800 V
  3. 2000 V
  4. None of the above

Correct Answer: 1800 V

Solution:

Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.

What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000

Practice Questions

Q1
What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
  1. 4500 V
  2. 1800 V
  3. 2000 V
  4. None of the above

Questions & Step-by-Step Solutions

What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
  • Step 1: Identify the formula for electric potential (V), which is V = k * q / r.
  • Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (charge) = 8 μC = 8 × 10^-6 C, and r (distance) = 4 m.
  • Step 3: Substitute the values into the formula: V = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m).
  • Step 4: Calculate the numerator: 9 × 10^9 * 8 × 10^-6 = 72,000.
  • Step 5: Divide the result by the distance: 72,000 / 4 = 18,000.
  • Step 6: The final result is V = 1800 V.
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