What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
Practice Questions
1 question
Q1
What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
4500 V
1800 V
2000 V
None of the above
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
Solution: Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Steps: 6
Step 1: Identify the formula for electric potential (V), which is V = k * q / r.
Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (charge) = 8 μC = 8 × 10^-6 C, and r (distance) = 4 m.
Step 3: Substitute the values into the formula: V = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m).
